I decided it would be a good use of my time to approximate e in terms of pi and approximate pi in terms of e
I challenge you to make a closer approximation than mine:
RULES:
Can use any operations
Choose 1 irrational number to use
Choose 1 irrational number to represent
You can only use that one irrational number to approximate the second one you chose
Get as close as you can without going over
Along with your approximation, provide a percentage in the form of 100(approximation)/(actual number)
165.381 days ago
Jan 19, 2022 - 3:03 PM
165.378 days ago
Jan 19, 2022 - 3:07 PM
I improved your approximation of pi in terms of eedit:
improved e in terms of pi tooedit 2: why approximate pi with e when you can find its exact value with e? arccos(e - e - e/e) is exactly equal to pi. Should we limit the set of legal operations?
159.367 days ago
Jan 25, 2022 - 3:23 PM
159.321 days ago
Jan 25, 2022 - 4:29 PM
159.321 days ago
Jan 25, 2022 - 4:29 PM
holy shit, mines only accurate to 4
159.32 days ago
Jan 25, 2022 - 4:31 PM
(Maclaurin series might be cheating)
159.319 days ago
Jan 25, 2022 - 4:32 PM
How did you manage this? (ninja'd, nvm)
159.319 days ago
Jan 25, 2022 - 4:32 PM
Maclaurin series. If you keep adding pi's over the first sigma, it'll keep converging (really fucking slowly, though).
159.319 days ago
Jan 25, 2022 - 4:32 PM
why did I think
this was a good idea
it didn't even work
159.308 days ago
Jan 25, 2022 - 4:48 PM
Pi, accurate to seven digits.
There was a trick I'm blanking on that you could use to make the pi series converge faster. Something to do with tangent?
why did I think
this was a good idea
Me when I look at how long that equation scrolls for:

159.305 days ago
Jan 25, 2022 - 4:52 PM
I see your Taylor Series and raise you a
continued fraction. It's already accurate enough, but you can make the pi^pi a proper power tower (pi^pi^pi^…) to make it converge real fast (and also
very difficult impossible to actually compute, because it's kinda overkill).
159.282 days ago
Jan 25, 2022 - 5:26 PM
This has now passed above my understanding
159.278 days ago
Jan 25, 2022 - 5:30 PM
I can do my best to explain further it if you'd like, but the gist is that continued fractions are great and e has a decently simple continued fraction.
159.273 days ago
Jan 25, 2022 - 5:39 PM
Can you make a continued fraction for pi?
159.272 days ago
Jan 25, 2022 - 5:40 PM
I see your continued fraction and raise you by
basically cheating (screenshot b/c I'm out for lunch and on my phone).
That's it, we've done it. It literally cannot be approximated any further.
159.269 days ago
Jan 25, 2022 - 5:44 PM
That's not an approximation to pi, that's just pi. Although I suppose you could just make it a Riemann Sum without too much effort.
And I did do a
continued fraction version for pi, but it does not converge quickly at all.
159.265 days ago
Jan 25, 2022 - 5:49 PM
Technically, an integral is an already-converged rsum if you thing about it.
159.264 days ago
Jan 25, 2022 - 5:51 PM
I just mean that if you view getting it exact as cheating then it would be trivial to get arbitrarily close.
159.263 days ago
Jan 25, 2022 - 5:53 PM
why did I think
this was a good idea
Me when I look at how long that equation scrolls for:

I was trying to implement Ramanujan's approximation but it had a four digit prime number
159.26 days ago
Jan 25, 2022 - 5:58 PM
This thread when it started: Fun ways of trying different combinations to come within a few hundredths of irrational numbers
This thread now: Nerdy arms race of applying progressively more convoluted methods in order to create impressively accurate approximations
159.236 days ago
Jan 25, 2022 - 6:32 PM
Maybe we should pick some numbers that are a little bit less well-researched than the two most famous transcendental numbers. Like, maybe we try approximating the
cosine fixed point in terms of the
Euler-Mascheroni constant.
159.214 days ago
Jan 25, 2022 - 7:03 PM
Maybe we should pick some numbers that are a little bit less well-researched than the two most famous transcendental numbers. Like, maybe we try approximating the
cosine fixed point in terms of the
Euler-Mascheroni constant.
I like that idea
here is my final submissions for approximating e
https://www.desmos.com/calculator/pmmgrmukgp159.2 days ago
Jan 25, 2022 - 7:23 PM
159.162 days ago
Jan 25, 2022 - 8:18 PM
Here is an extremely simple one
π = 3√31
99.993% accuracy
I challenge you all to find an approximation as simple with a better accuracy
Edit: I have just realized that this forum is like 3 months old and I don't even care. I demand that the abyss answer my call.
84.979 days ago
Apr 10, 2022 - 12:42 AM
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"time": "1642604583",
"html": "I decided it would be a good use of my time to approximate e in terms of pi and approximate pi in terms of e<br /><br />I challenge you to make a closer approximation than mine:<br /><br /><span style=\"font-weight:bold;\"><span style=\"text-decoration:underline;\">RULES:</span></span><br />Can use any operations<br />Choose 1 irrational number to use<br />Choose 1 irrational number to represent<br />You can only use that one irrational number to approximate the second one you chose<br />Get as close as you can without going over<br />Along with your approximation, provide a percentage in the form of 100(approximation)/(actual number)",
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{
"id": "1186067",
"time": "1642604821",
"html": "here are my 2 entries so far<br /><br /><a href=\"https://www.desmos.com/calculator/nhyk1ukxws\">approximation of pi in terms of e</a><br /><a href=\"https://www.desmos.com/calculator/qq1omkbok3\">approximation of e in terms of pi</a><br /><br /><div style=\"font-style:italic;color:#888;\"> also just for fun: <a href=\"https://www.desmos.com/calculator/rg8iw8z1yw\">approximation of 8 in case you need to use it on the fly</a></div>",
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{
"id": "1188479",
"time": "1643124237",
"html": "<a href=\"https://www.desmos.com/calculator/qx0jrkwpun\">I improved your approximation of pi in terms of e</a><br /><br />edit: <a href=\"https://www.desmos.com/calculator/4akpwzbgzh\">improved e in terms of pi too</a><br /><br />edit 2: why approximate pi with e when you can find its exact value with e? arccos(e - e - e/e) is exactly equal to pi. Should we limit the set of legal operations?",
"user": "aprzn123"
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{
"id": "1188533",
"time": "1643128163",
"html": "<a href=\"https://www.desmos.com/calculator/tr4zdtuzus\">I feel I might have over-approximated</a><br />Accurate to 16 digits",
"user": "kylijoy"
},
{
"id": "1188534",
"time": "1643128196",
"html": "<a href=\"https://www.desmos.com/calculator/zpsz8zhdn1\">improved on the approximation of e in terms of pi</a><br /><br />working on the pi in terms of e<br /><br />ninjad damn",
"user": "dementedkermit"
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{
"id": "1188535",
"time": "1643128282",
"html": "<div style=\"margin:20px; background-image:url(/images/light.png);\"><div style=\"border:1px solid #888; padding:5px;\"><a href=\"/users/kylijoy\">KylIjoy</a> said:</div><div style=\"border:1px solid #888; padding:20px;\"><a href=\"https://www.desmos.com/calculator/tr4zdtuzus\">I feel I might have over-approximated</a><br />Accurate to 16 digits</div></div><br />holy shit, mines only accurate to 4",
"user": "dementedkermit"
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{
"id": "1188536",
"time": "1643128332",
"html": "(Maclaurin series might be cheating)",
"user": "kylijoy"
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{
"id": "1188538",
"time": "1643128351",
"html": "<div style=\"margin:20px; background-image:url(/images/light.png);\"><div style=\"border:1px solid #888; padding:5px;\"><a href=\"/users/kylijoy\">KylIjoy</a> said:</div><div style=\"border:1px solid #888; padding:20px;\"><a href=\"https://www.desmos.com/calculator/tr4zdtuzus\">I feel I might have over-approximated</a><br />Accurate to 16 digits</div></div><br />How did you manage this? (ninja'd, nvm)",
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"id": "1188539",
"time": "1643128378",
"html": "Maclaurin series. If you keep adding pi's over the first sigma, it'll keep converging (really fucking slowly, though).",
"user": "kylijoy"
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{
"id": "1188548",
"time": "1643129317",
"html": "why did I think <a href=\"https://www.desmos.com/calculator/ynsglyadss\">this</a> was a good idea<br />it didn't even work",
"user": "aprzn123"
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{
"id": "1188549",
"time": "1643129532",
"html": "<a href=\"https://www.desmos.com/calculator/nxsgimdzlb\">Pi, accurate to seven digits</a>.<br />There was a trick I'm blanking on that you could use to make the pi series converge faster. Something to do with tangent?<br /><div style=\"margin:20px; background-image:url(/images/light.png);\"><div style=\"border:1px solid #888; padding:5px;\"><a href=\"/users/aprzn123\">aprzn123</a> said:</div><div style=\"border:1px solid #888; padding:20px;\">why did I think <a href=\"https://www.desmos.com/calculator/ynsglyadss\">this</a> was a good idea</div></div><br />Me when I look at how long that equation scrolls for:<br /><img src=\"https://i.imgur.com/zdILJXS.png\" alt=\"\" />",
"user": "kylijoy"
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{
"id": "1188568",
"time": "1643131574",
"html": "I see your Taylor Series and raise you a <a href=\"https://www.wolframalpha.com/input/?i=%28%28pi%2Bpi%29%2Fpi%29%2Bcontinuedfractionk%28pi%2Fpi%2B%28mod%28k%2C%28pi%2Bpi%2Bpi%29%2Fpi%29*%28pi%2Bpi%29%2Fpi-mod%28k%2C%28pi%2Bpi%2Bpi%29%2Fpi%29%5E%28%28pi%2Bpi%29%2Fpi%29%29*%28%28pi%2Bpi%29k%2Bpi%29%2F%28pi%2Bpi%2Bpi%29%2C+%28k%2C+pi-pi%2C+floor%28pi%5Epi%29%29%29\">continued fraction</a>. It's already accurate enough, but you can make the pi^pi a proper power tower (pi^pi^pi^\u2026) to make it converge real fast (and also <span style=\"text-decoration:line-through;\">very difficult</span> impossible to actually compute, because it's kinda overkill).",
"user": "justabitjaded"
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"time": "1643131851",
"html": "This has now passed above my understanding",
"user": "dementedkermit"
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{
"id": "1188577",
"time": "1643132361",
"html": "I can do my best to explain further it if you'd like, but the gist is that continued fractions are great and e has a decently simple continued fraction.",
"user": "justabitjaded"
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{
"id": "1188578",
"time": "1643132442",
"html": "Can you make a continued fraction for pi?",
"user": "dementedkermit"
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{
"id": "1188579",
"time": "1643132641",
"html": "I see your continued fraction and raise you by <a href=\"https://imgur.com/a/JIckAek\">basically cheating</a> (screenshot b/c I'm out for lunch and on my phone).<br /><br />That's it, we've done it. It literally cannot be approximated any further.",
"user": "kyiijoy"
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{
"id": "1188581",
"time": "1643132975",
"html": "That's not an approximation to pi, that's just pi. Although I suppose you could just make it a Riemann Sum without too much effort.<br /><br />And I did do a <a href=\"https://www.wolframalpha.com/input/?i=ceil%28e%29%2Bcontinuedfractionk%28%28floor%28e%29*k-e%2Fe%29%5Efloor%28e%29%2C+ceil%28e%29%2Bceil%28e%29%2C+%28k%2C+e%2Fe%2C+ceil%28e*e%5Ee%29%29%29\">continued fraction version for pi</a>, but it does not converge quickly at all.",
"user": "justabitjaded"
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"time": "1643133085",
"html": "Technically, an integral is an already-converged rsum if you thing about it.",
"user": "kyiijoy"
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{
"id": "1188585",
"time": "1643133182",
"html": "I just mean that if you view getting it exact as cheating then it would be trivial to get arbitrarily close.",
"user": "justabitjaded"
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{
"id": "1188589",
"time": "1643133489",
"html": "<div style=\"margin:20px; background-image:url(/images/light.png);\"><div style=\"border:1px solid #888; padding:5px;\"><a href=\"/users/kylijoy\">KylIjoy</a> said:</div><div style=\"border:1px solid #888; padding:20px;\"><div style=\"margin:20px; background-image:url(/images/light.png);\"><div style=\"border:1px solid #888; padding:5px;\"><a href=\"/users/aprzn123\">aprzn123</a> said:</div><div style=\"border:1px solid #888; padding:20px;\">why did I think <a href=\"https://www.desmos.com/calculator/ynsglyadss\">this</a> was a good idea</div></div><br />Me when I look at how long that equation scrolls for:<br /><img src=\"https://i.imgur.com/zdILJXS.png\" alt=\"\" /></div></div><br />I was trying to implement Ramanujan's approximation but it had a four digit prime number",
"user": "aprzn123"
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{
"id": "1188599",
"time": "1643135536",
"html": "This thread when it started: <span style=\"font-style:italic;\">Fun ways of trying different combinations to come within a few hundredths of irrational numbers</span><br /><br />This thread now: <span style=\"font-weight:bold;\">Nerdy arms race of applying progressively more convoluted methods in order to create impressively accurate approximations</span>",
"user": "kylijoy"
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{
"id": "1188602",
"time": "1643137413",
"html": "Maybe we should pick some numbers that are a little bit less well-researched than the two most famous transcendental numbers. Like, maybe we try approximating the <a href=\"https://en.wikipedia.org/wiki/Dottie_number\">cosine fixed point</a> in terms of the <a href=\"https://en.wikipedia.org/wiki/Euler%27s_constant\">Euler-Mascheroni constant</a>.",
"user": "justabitjaded"
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{
"id": "1188605",
"time": "1643138604",
"html": "<div style=\"margin:20px; background-image:url(/images/light.png);\"><div style=\"border:1px solid #888; padding:5px;\"><a href=\"/users/justabitjaded\">justabitjaded</a> said:</div><div style=\"border:1px solid #888; padding:20px;\">Maybe we should pick some numbers that are a little bit less well-researched than the two most famous transcendental numbers. Like, maybe we try approximating the <a href=\"https://en.wikipedia.org/wiki/Dottie_number\">cosine fixed point</a> in terms of the <a href=\"https://en.wikipedia.org/wiki/Euler%27s_constant\">Euler-Mascheroni constant</a>.</div></div><br />I like that idea<br /><br />here is my final submissions for approximating e<br /><a href=\"https://www.desmos.com/calculator/pmmgrmukgp\">https://www.desmos.com/calculator/pmmgrmukgp</a>",
"user": "dementedkermit"
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"id": "1188615",
"time": "1643141920",
"html": "<a href=\"https://www.desmos.com/calculator/x7yaft2bha\">it feels like cheating to use a number less than 1: approximating dottie number using sqrt(i^i)</a>",
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"html": "Here is an extremely simple one<br /><br />\u03c0 = <sup>3</sup>\u221a31<br /><br />99.993% accuracy<br /><br />I challenge you all to find an approximation as simple with a better accuracy<br /><br />Edit: I have just realized that this forum is like 3 months old and I don't even care. I demand that the abyss answer my call.",
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